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Created attachment 18021 [details]
Example programm that demonstrate the exception
I call IOControl with IOControlCode.RoutingInterfaceQuery to determine routing information.
On Windows with MS-.Net i get the correct information.
On Linux with Mono 4.4.0 i get e SocketException with a dubious message:
"System.Net.Sockets.SocketException: The descriptor is not a socket"
I have attached a sample Program that show the error
You must set ip/port to connect to (telnet service, web, ....)
I think this is a wrong implementation in mono.
I have testet with mono 4.4.0 and 4.6.1. same result.
Hi Mario, I tried with master and cannot reproduce it. Could you please confirm if you can reproduce with mono 4.8.0? Thank you.
I'm on Mono JIT compiler version 4.8.1 (Stable 188.8.131.52/22a39d7 Wed Apr 12 12:00:40 UTC 2017)
I've just tested Mario's program and can confirm the output is as reported.
The descriptor is not a socket
[ERROR] FATAL UNHANDLED EXCEPTION: System.Net.Sockets.SocketException (0x80004005): The descriptor is not a socket
I believe the problem is that Linux does not expose a comparable syscall which accepts a RoutingInterfaceQuery IOCTL. This is Windows specific control code.
An end-user would rely on the iproute2 package to find the ip address of the gateway exposing a route to a given destination
$ ip route get 184.108.40.206
But as you can see from the iproute_get() function in iproute2's source code https://github.com/shemminger/iproute2/blob/707f612c00a91fe3c17d7af5319e423545a496c5/ip/iproute.c it involves several syscalls, not one clean RoutingInterfaceQuery request.
I don't know if anybody will find it useful, but short of the Mono team implementing a comparable API, you can bind a datagram Socket and Connect() to the address that you would have passed into RoutingInterfaceQuery.
Read the LocalEndPoint off the Socket to get your route.
private static IPAddress GetRouteLinux(IPAddress destionationIpAddress)
using (var socket = new Socket(AddressFamily.InterNetwork, SocketType.Dgram, 0))
return ((IPEndPoint) socket.LocalEndPoint).Address;
catch (Exception ex)
As pointed out in https://bugzilla.xamarin.com/show_bug.cgi?id=45364#c3 this feature is not readily available on Linux, and a workaround has been provided.